CalculatorUser

at least next year they give us 75 min.

but problem 8 is like problem 25 on the amc 8

Largest score. - 6 * 25 = 150

Score with nothing answered - 2 * 25 = 50

Lowest score - 0

From 0 - 50 we have 50/2 = 25 possible scores because the points go up by 2.

From 50 - 150 we have 150 - 50 = 100, then since the points up by 4. (6 - 2 = 4)

100/4 = 25

25 + 25 = 50 possible scores

my math abilities take time. I usually take a long time to think..

with 40 minutes, I ripped. It was the timing I did not get used to.

I know what I did wrong

Oh ok, I know what I did wrong.

Basically I got to a certain point where 2, 3, 5, can be substituted in here:

\(x^2*y^2*z\)
Then, I find all the possible values, and count them.

I thought it was just 3!, but if you calculated it out, it actually is 3.

Dunno, is this helpful to you?

Credit to CPhill

Just to be sure, does [ABC] mean area?

Yup I understand,

but I don't understand how do you know the angle bisector of BAC is going to be the shortest segment...

Is there a theorem on this?

Wait Oh I think we learned in class that the smaller the angle, the LONGER the segment.

So the BIGGER the angle, the SMALLER the segment.

but if we know that the angles are divided into two congruent parts, how do we solve knowing the sides.

I mean, I try to refrain from cheating with Trigonometry, so below is the info I gathered.

Since the angle is bisected, we have

4x + y = 180.

Y is the vertex angle, and x is one of the base angles that are bisected, so there are total 4 of them.

I cannot find any special triangles anywhere....

Oof haven't learned matrices yet...

Welp I can only solve some competition problems,

Yeah I was trying to get the guest to reply because I was confused by "do the see"