2sin(2x)+ sqrt3 = 0 subtract square root 3 from both sides
2sin2x = -√3 divide both sides by 2
sin2x = -√3 / 2
sin x = -√3 / 2 at 240° and at 300°
So sin 2x = -√3 / 2 at 120° and at 150°
More general solutions are 120° + (2pi)n and 150° + (2pi)n where n is an integer
