Derekshakk

Answer:

15 6/7

Explanation:

The roots of 7x^2 + x - 5 = 0 are a and b.

Compute (a - 4)(b - 4).

Use of this information:

For the quadratic equation ax^2+bx+c=0, the sum of its roots = –b/a and the product of its roots = c/a.

In given case:

sum of roots=a+b= - 1/7

product of roots=ab= -5/7

Now let's find the value of (a-4)(b-4)

(a-4)(b-4)=

ab-4(a+b)+16=

-5/7-4(-1/7)+16=

-1/7+16=

15 6/7

The answer is 15 6/7

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ur Welcome :D

1/36 ?

OOOMMMGGGGG TYSM CPHILL!!!!!!! :D

y=ax³+bx²+cx+d
the constant term is d


if their polynomials have the same constant term  then the product is
(ax³+bx²+cx+d)(rx³+ex²+vx+d)
the only thing we know is the constant terms are the same
we notice that the last term of the product will be the product of the constant terms

so the last term will be d²

the last term is 16
d²=16
sqrt both sides
d=4

the constant term of Jamie's polynomial is 4

Since b^2 - 4ac must be greater than 0 in order to have at least one real number solution, you can plug it in:

25 - 8c > 0

8c < 25

c < 25/8

As a result, your answer is 25/8.

:D Hope this helps.

a) 12 students

b) 32 students

.009009009  =   9/999  = 1/111

And 1 * 111 =   111

The length of the diameter of the circle is equal to the square's side length. The side length of the square is 8 inches. Therefore, the circumference of the circle is 8 pi inches.