What is the product of the numerator and the denominator when $0.\overline{09}$ is expressed as a fraction in lowest terms?

 Apr 3, 2021

I'm not sure how to explain this, but when you have a line, the fraction denominator is the number of digits and 9 amount of that. 

So under this line, there are 2 digits, so the denominator is 2 nines, 99. 

The numberator is the number under the line, 9. 

So our fraction is 9/99 = 1/11.

That would make the product 11. 

Sorry for the sad explanation. 

I hope this helped. :))



 Apr 3, 2021

There is an algebraic way through manipulation:


Let $x=0.\overline{09}$


Multiply by 100 to get $100x=9.\overline{09}$


Subtract x from 100x to get $100x-x=9.\overline{09}-0.{09}$ which cancels out the infinite decimals leaving $99x=9$


Dividing both sides by 99 gives $x=\frac{9}{99}$, which simplifies to $x=\frac{1}{11}$. The product of the numerator and denominator is $1*11=\boxed{11}$


If you are familiar with geometric series there is also another way:




simplifying gives x=9*10^-2+9*10^-4+9*10^-6+... (you got lucky the 0's canceled out, there is a trick to dealing with them when there is no 0's to cancel out)


We can see this is an infinite geometric series with first term 9*10^-2 and common ration 10^-2. Using the formula for the sum of an infinite geometric series gives:







The product is 11 :) These are the two algebraic solutions

 Apr 3, 2021

.009009009  =   9/999  = 1/111


And 1 * 111 =   111

 Apr 3, 2021

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