+0  
 
+1
73
2
avatar+62 

Ben twice chooses a random integer between 1 and 50, inclusive (and he may choose the same integer both times). What is the probability that at least one of the numbers Ben chooses is a multiple of 3?

 May 31, 2021
 #1
avatar
-1

There are 16 numbers that are divisible by 3 from 1 to 50, so the probability is 16/50*16/50 = 64/625.

 May 31, 2021
 #2
avatar+114069 
+1

Nice try, but...

 

What you have found is the prob that he chooses a number divsiable by 3 both times.  

 

Can you fix it?

Melody  Jun 5, 2021

19 Online Users

avatar
avatar