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What is the largest number c such that \(2x^2+5x+c=0\) has at least one real solution? Express your answer as a common fraction.

 Apr 8, 2021
 #1
avatar+29 
+3

Since b^2 - 4ac must be greater than 0 in order to have at least one real number solution, you can plug it in:

25 - 8c > 0

8c < 25

c < 25/8

As a result, your answer is 25/8.

 

:D Hope this helps.

 Apr 9, 2021
 #2
avatar+31826 
+1

To be mathematically correct   c25/8       as the determinant can = 0

ElectricPavlov  Apr 9, 2021

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