+62 Answer:
15 6/7
Explanation:
The roots of 7x^2 + x - 5 = 0 are a and b.
Compute (a - 4)(b - 4).
Use of this information:
For the quadratic equation ax^2+bx+c=0, the sum of its roots = –b/a and the product of its roots = c/a.
In given case:
sum of roots=a+b= - 1/7
product of roots=ab= -5/7
Now let's find the value of (a-4)(b-4)
(a-4)(b-4)=
ab-4(a+b)+16=
-5/7-4(-1/7)+16=
-1/7+16=
15 6/7
The answer is 15 6/7
👍🏻👍🏻👍🏻
+62 Answer:
15 6/7
Explanation:
The roots of 7x^2 + x - 5 = 0 are a and b.
Compute (a - 4)(b - 4).
Use of this information:
For the quadratic equation ax^2+bx+c=0, the sum of its roots = –b/a and the product of its roots = c/a.
In given case:
sum of roots=a+b= - 1/7
product of roots=ab= -5/7
Now let's find the value of (a-4)(b-4)
(a-4)(b-4)=
ab-4(a+b)+16=
-5/7-4(-1/7)+16=
-1/7+16=
15 6/7
The answer is 15 6/7
👍🏻👍🏻👍🏻
