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Find three consecutive odd integers such that eight more than the sum of the first two is equal to eleven less than three times the third. Find the THIRD number.

 

a) 9

b) 11

c) 13

d) 15

 Sep 11, 2020
 #1
avatar+26763 
+1

Numbers are   x    x+2     and     x+4

    x   +   x+2     + 8     =  3 (x+4) - 11       solve for 'x'    then the third number is    x+4

 Sep 11, 2020
 #2
avatar+1220 
0

I see now. I put 11 - 3 in the beginning so I had -3 times everything.

SmartMathMan  Sep 11, 2020

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