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Jill has a coin collection. She has 21 coins in all. She has 4 times as many pennies as nickels. She has 1 more dime than the number of nickels. She has 1 less quarter than the number of nickels. How many of each coin does she have?

 

a 12 pennies, 3 nickels, 4 dimes, and 2 quarters

 

b) 16 pennies, 4 nickels, 5 dimes, and 3 quarters

 

c) 12 pennies, 3 nickels, 2 dimes, and 4 quarters

 

d) 16 pennies, 4 nickels, 3 dimes, and 5 quarters

 Sep 11, 2020
 #1
avatar+37146 
+1

21 coins

 

n

p = 4n

d = n+1

q = n-1

n  +  4n  +   n+1    +   n-1 = 21

7n = =21

n = 3

 

then   p = 12      d = 4   q = 2

 Sep 11, 2020
 #2
avatar+1443 
+1

Thank you!! I'm really trying to learn how to do these problems. 

SmartMathMan  Sep 11, 2020

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