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Find the radius of the following circle

x^2+16+y^2-4y+16=0

 Sep 12, 2020
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x^2+16x+y^2-4y+16=0        put in standard form     (x-h)^2 + (y-k)^2 = r ^2

                                                    by completing the squre for x any

(x+8)^2  + ( y-2)^2 = -16 +64 + 4        r^2 = 52

 Sep 12, 2020

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