The first side of a triangle is 3 times as long as the third side. The third side is five feet shorter than twice the length of the second side. If the perimeter of the triangle is 52 feet, what is the length of the first side?
t
f = 3t
t = 2s-5 s = (t+5)/2 all three sides sum to 52
t + 3t + (t+5)/2 = 52 solve for t then f = 3t and s = (t+5)/2