20x2 + 22xy + 6y2 = 2(10x2 + 11xy + 3y2) = 2(5x+3y)(2x+y)
96x^2-6y^2
Factoring out 6 from (96x2−6y2), we get:
6(16x2−y2)
Factoring the equation above:
6(4x−y)(4x+y)→ final answer
Checking using FOIL method:
(4x−y)(4x+y)=16x2+4xy−4xy−y2=16x2−y2
6(16x2−y2)=(96x2−6y2)
Did I do it right???
square root of 273.64
16.5420675854
Pftt. And Bruce was telling us that we were wrong.. :/
6x² + 10xy - 4y² = 2 (3x² + 5xy - 2y²) = 2 (3x² + 6xy - xy - 2y²) = 2 (3x (x + 2y) - y (x + 2y)) = 2 (x + 2y) (3x - y)
I JUST had a problem like this yesterday!!
So I coppied it from my work. Hopefully It's right!
All I was doing was sipping on root beer! Gosh :l
* sips on root Beer*
Hmm
can you factor 27x^6+64y^12
27x^6 +64y^3 you need to look at the way to factor a^3 + b^3: a^3 + b^3 = (a + b)(a^2 - ab + b^2) cube root of 27x^6 = 3x^2 cube root of 64y^3 = 4y so: 27x^6 +64y^3 = (3x^2 + 4y)(9y^4 - 12x^2 * y + 16y^2)
Thank you :D
