can you factor 27x^6+64y^12
27x^6 +64y^3 you need to look at the way to factor a^3 + b^3: a^3 + b^3 = (a + b)(a^2 - ab + b^2) cube root of 27x^6 = 3x^2 cube root of 64y^3 = 4y so: 27x^6 +64y^3 = (3x^2 + 4y)(9y^4 - 12x^2 * y + 16y^2)
You're on a roll, kid....!!!!!
[Don't forget to give yourself 5 pts.....!!!! ]
