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20x^2+22xy+6y^2

 Feb 2, 2016

Best Answer 

 #2
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  20x2 + 22xy + 6y2 = 2(10x2 + 11xy + 3y2) = 2(5x+3y)(2x+y)

 Feb 2, 2016
 #1
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Factor the following: 20 x^2+22 x y+6 y^2 Factor 2 out of 20 x^2+22 x y+6 y^2: 2 (10 x^2+11 x y+3 y^2) The coefficient of x^2 is 10 and the coefficient of y^2 is 3. The product of 10 and 3 is 30. The factors of 30 which sum to 11 are 5 and 6. So 10 x^2+11 x y+3 y^2 = 10 x^2+6 x y+5 x y+3 y^2 = 5 x (2 x+y)+3 y (2 x+y): 2 5 x (2 x+y)+3 y (2 x+y) Factor 2 x+y from 5 x (2 x+y)+3 y (2 x+y): Answer: | | 2 (2 x+y) (5 x+3 y)

 Feb 2, 2016
 #2
avatar+8581 
+10
Best Answer

  20x2 + 22xy + 6y2 = 2(10x2 + 11xy + 3y2) = 2(5x+3y)(2x+y)

Hayley1 Feb 2, 2016

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