The Ratio of reds to greens was 4 to 11 and 60 percent of the greens exceeded the number of reds by 52. How many were red and how many were green?
Please show how to solve. Thanks!
+129850 Good job, Hayley.......!!!!!!..........let's confirm her answer
Reds / Greens = 4/11 so
Reds = Greens*(4/11)
And we have that
.60Greens - Reds = 52
(6/10)Greens - (4/11)Greens = 52
(3/5)Greens - (4/11)Greens = 52
([33 - 20]/55 ) Greens = 52
[13/55]Greens = 52 multiply both sides by 55/13
Greens = [52/13]*55 = 4*55 = 220
And the Reds = 4/11 of this = 80
And .60(220) - 80 = 52
Just as Hayley found !!!!! [ 5 pts. from me......]
+8581 The Ratio of reds to greens was 4 to 11 and 60 percent of the greens exceeded the number of reds by 52. How many were red and how many were green?
You can form two equations:
green*0.6 - red = 52 ...........(1)
green / red = 11/4 ...........(2)
from (2) red = 4*green/11 and then substitute red into (1) to solve for green.
you'll get green = 110*52/26 = 220 and use 220/11 to get red =20.
+129850 Good job, Hayley.......!!!!!!..........let's confirm her answer
Reds / Greens = 4/11 so
Reds = Greens*(4/11)
And we have that
.60Greens - Reds = 52
(6/10)Greens - (4/11)Greens = 52
(3/5)Greens - (4/11)Greens = 52
([33 - 20]/55 ) Greens = 52
[13/55]Greens = 52 multiply both sides by 55/13
Greens = [52/13]*55 = 4*55 = 220
And the Reds = 4/11 of this = 80
And .60(220) - 80 = 52
Just as Hayley found !!!!! [ 5 pts. from me......]
The Ratio of reds to greens was 4 to 11 and 60 percent of the greens exceeded the number of reds by 52. How many were red and how many were green?
Please show how to solve. Thanks!
Let the number of Reds=R
Number of greens=11/4R
.60(11/4)R - R =52, so we have:
Reds=80
Greens=220
Solve for R: 0.65 R = 52 Divide both sides of 0.65 R = 52 by 0.65: (0.65 R)/0.65 = 52/0.65 0.65/0.65 = 1: R = 52/0.65 52/0.65 = 80.: Answer: | | R = 80.
