hectictar

volume of pyramid  =  (1/3)(area of base)(height)

area of square base  =  751 * 751  ft²   =   564001  ft²       Plug this in for  area of base.

                                                                                            Plug in the height given in the problem.

volume of pyramid  =  (1/3)(564001 ft²)(481 ft)                   Multiply these together.

volume of pyramid  ≈  90 428 160   ft³

And    90 428 160   ≈   9.0 * 10⁷

volume   =   (1/3)(area of base)(height)        Plug in the information from the problem.

volume   =   (1/3)(24)(6)    cubic inches

Evaluate this to get your answer.    

I tried to but I couldn't get it.....someone else on here might know a way though.

1)     When  y = 0 ,  x = 1, 3,  or  -4

A polynomial in that form with zeros at  1, 3,  and  -4  is

y  =  a(x - 1)(x - 3)(x + 4)

To find  a , plug in  -1  for  x  and  2  for  y .

2  =  a(-1 - 1)(-1 - 3)(-1 + 4)

2  =  a(-2)(-4)(3)

2  =  24a

a  =  1/12

I'll give it a  " shot "   

Define units for the additional practice time and the time spent working on shooting skills.

hours  and  hours

Then enter a variable for the additional practice time. . . (additional to the 18 hours)

x                        --  this is the expression for Additional Practice Time.

. . .and use this variable to write an expression for the time spent working on shooting skills.

\(\frac34\)(x + 18)           -- this is the expression for  Time Spent Shooting.

Question 1

For Additional Practice Time, we are given  51

So Time Spent Shooting  =  \(\frac34\)(51 + 18)  , which  =  51.75

Question 2

For Time Spent Shooting, we are given  55.5

Additional Practice Time  =  x   and   \(\frac34\)(x + 18)  =  55.5

\(\frac34\)(x + 18)   =   55.5           Multiply both sides of this equation by  4/3

x + 18   =   74                   Subtract  18  from both sides

x   =   56   =   Additional Practice Time

Question 3

For Additional Practice Time, we are given  46

So Time Spent Shooting  =    ..... (Can you finish it??)

volume   =   (area of base) * (height)

area of base   =   pi * radius²   =   pi * (1.75/2)²   =   49pi / 64

volume   =   (49pi / 64) * (5.25)   =   1029pi / 256   ≈   12.628  cubic units

Also the diameter and height must be measured in the same units.

Also the weight doesn't affect its volume.   

e.   To make factoring easier, rearrange the 25 - 20x + 4x^{2 .}

     \(\frac{6x^2-11x-10}{6x^2-5x-6}\cdot\frac{6-4x}{4x^2-20x+25}\)

Now we need to factor all the numerators and denominators. Start by splitting their middle terms.

=   \(\frac{6x^2+4x-15x-10}{6x^2-9x+4x-6}\cdot\frac{6-4x}{4x^2-10x-10x+25}\)

                                                                            Now factor by grouping.

=   \(\frac{2x(3x+2)-5(3x+2)}{3x(2x-3)+2(2x-3)}\cdot\frac{6-4x}{2x(2x-5)-5(2x-5)}\)

=   \(\frac{(3x+2)(2x-5)}{(2x-3)(3x+2)}\cdot\frac{-2(2x-3)}{(2x-5)(2x-5)}\)

                                                                           Multiply the fractions together.

=   \(\frac{(3x+2)(2x-5)(-2)(2x-3)}{(2x-3)(3x+2)(2x-5)(2x-5)}\)

                                                                           Cancel the common terms.

=   \(\frac{{\color{red}(3x+2)}{\color{red}(2x-5)}(-2){\color{red}(2x-3)}}{{\color{red}(2x-3)(3x+2)(2x-5)}(2x-5)}\)

=   \(\frac{(-2)}{(2x-5)}\)

=   - \(\frac{2}{2x-5}\)

And  x  ≠  3/2  or  -2/3   since these cause a zero in the denominator of the original expression.

No, I said it is not me.

It's not me...but....are you sure that whoever it is, is cool with you posting that picture?

If it were me, I would not be cool with it.

The distance from the center of the circle to each of the  3  points will be the same.

We can call this distance  " r "  for radius.  So we know...

(-1 - a)² + (0 - b)²  =  r²

(1 - a)² + (0 - b)²  =  r²            And...

(3 - a)² + (1 - b)²  =  r²

Set the first two values of  r²  equal to each other.

(-1 - a)²  + b²  =  (1 - a)² + b²

                                                      Subtract  b²  from both sides.

(-1 - a)²  =  (1 - a)²

                                                      Take the  ±  square root of both sides.

-1 - a  =  ±(1 - a)

-1 - a  =  1 - a     or     -1 - a  =  -1 + a     →     a  =  0

Using this value for  a , set the second and third values of  r²  equal to each other.

(1 - 0)² + b²  =  3² + (1 - b)²           Solve this for  b .

1 + b²  =  9 + 1 - 2b + b²

1  =  10 - 2b

-9  =  -2b

9/2  =  b