helperid1839321

I would guess that our senses of humor differ notably then, as I wasn't able to detect much humor or anything to laugh at in the post. In any case, the point of not having the original question in the repost still stands.

Assuming we can't choose the same 2 points:

We have 3 points in the same column, or 4 points in the same row, that are valid points to choose, that would result in the dots making a row or column.

Out of the 19 other points you can choose after the first one, there are 7 that match the initial condition.

Therefore, the probability is 7/19.

Sorry I don't have a better explanation, but I'm not really a fan of using latex to make graphics.
... You know what, I'll do it anyways

Here's an example. X is the point we choose, C are the dots that make a vertical line, and R are the ones that make a horizontal line.

\(\begin{bmatrix}X & R & R & R & R \\ C &&&&\\ C &&&&\\ C &&&&\end{bmatrix}\)

Not sure why you would go through the effort of pressing enter so many times, but I might as well put a full walkthrough here.

The guest is correct, the critical information here is that C + D + E = 180, along with the relations.

So, let's expand it through substitution.

4x - 16 + 6x - 1 + 4x - 13 = 180

We can also group the terms using the commutative property, making this a lot easier to look at: 

14x - 30 = 180

Now, we solve a single-variable equation.

14x = 210

7x = 105

x = 15

.

Now, let's plug this value of x back into the equation for angle C.

C = 4x - 16
C = 4*15 - 16

C = 60 - 16
C = 44

Thus, angle C has a measure of 44 degrees.

And guest, I like the fact that you didn't give the answer right away but instead gave a hint to solve the problem, that's better than a number of other guest posts I've seen on here as answers :D

I've already mentioned this to another user, but simply posting a link without the original question is not generally seen as a productive way to attract an answer. If the question has been buried and needs an answer, general policy is that it's grounds to repost the orginal question, optionally with a link to the original post, as far as I remember.

The title isn't necessarily helpful either, as it doesn't indicate what the problem was. It's quite possible not many people saw it or had someone else to help or something else to do. We don't trawl this forum all day and appreciate having other things we can do with our lives.

Just a kind message asking you to please refrain from doing this in the future, thank you for listening.

This one appears solvable without graphing or using a calculator due to one quirk:
Take another look at those equations for the circles

(x-2)² + (y-3)² = 9

(x-2)² + (y+4)² = 16

The x-term in each equation is actually identical. We can therefore eliminate each from the equation for the purposes of solving for y.
We'll also expand the y-term here for convenience in the next step.

y² - 6y + 9 = 9
y² + 8y + 16 = 16

We can also eliminate the term y² here as it's shared on both sides. We can also take out the constant values on both sides, giving us...

-6y = 0

8y = 0

Through multiplication of each equation we can get y = 0. Now plugging this into the original equations...

(x-2)² + (0-3)² = 9

(x-2)² + (0+4)² = 16
 

(x-2)² + (-3)² = 90

(x-2)² + (4)² = 16

(x-2)² + 9 = 9

(x-2)² + 16 = 16

(x-2)² = 0

(x-2)² = 0

Taking square root of both sides...

x-2 = 0

x-2 = 0

x = 2

x = 2

Going back, we now have 2 solutions for (2, 0). Thus, the question is worded misleadingly, and the only intersection is at (2, 0)

Let's make a system of equations to express the system to make it easier to not make a mistake (as the guest answerer unfortunately did).
 

m = max's baseball cards
p = pauls baseball cards

5p = m
p + 28 = m
 

... using substitution of the term m...
 

5p = p + 28

4p = 28
p = 7

... solve for m...

5p = m
5*7 = m
m = 35

Therefore, Max has 35 baseball cards.

I'm going left to right with the multiplication. Q is across the top, E is down the left.\(\left.\begin{matrix} &11&-5i\\ 3&33&-15i\\ -2i&-22i&-10 \end{matrix}\right] = 23 - 37i\).

Now, we multiply QE by D. \((23-37i) \times 2i = QE \times D = QED = 46i + 74\).
 

Remember, i * i = -1, and -i * i = 1. i is effectively a variable until you are dealing with more than one of them being multiplied.

I think the term for this is "abstract quantity"? It's a value you use like a variable with some exceptions.

This response was not very productive, and does not provide me with any helpful feedback to use to improve. Feedback with the objective of helping people grow would be appreciated more than a response with little thought, depth, or room to grow from. Thank you :)