+0  
 
+1
238
2
avatar+541 

I was doing my math on this calculator when I came to a problem that required me to find a and b for the setup \(solve(ab=11,a+b=6)\)

I put it in the calculator and I got: {ab=11, a=6-r1, b=r1}.

What is the r1, and where is it coming from?

helperid1839321  Nov 4, 2017
 #1
avatar+26720 
+3

The calculator doesn’t understand your implicit multiplication, so you need to enter a*b=11, not ab =11. If you do this the calculator produces the correct two (complex) results.

In your case, the calculator simply ignored the ab=11 part and assigned an arbitrary variable, r1, to b and then solved for a as a = 6 - b → 6 - r1.

Alan  Nov 5, 2017
 #2
avatar+541 
0

Thank you!

cool

helperid1839321  Nov 9, 2017

21 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.