hugomimihu

I normally would ask "did you go on break" but then that's not exactly possible right now.

Good to see you back Melody's probably been overtaxed! LOL

actually.

I suppose you multiply all numbers except for 1, and add 1. 

a) 19+ 7/2 - 5 = 19 +3.5 -5 = 22.5 -5 = 17.5

b) well if we put parenthesis around 19 and 7 = 26/2 = 13, -5 = 8

c) 19 + 7 / 2 * 6 +1

If we put parenthesis around 19 and 7 it's 26, but 2*6 + 1 = 13, so 26/13 = 2. 

If you don't understand anything feel free to ask.

Also if you just want to understand questions from site 2, why do you post site 1 as well??? Confused

Let us find the prime factorization of 600.

600 = 2 * 300

                / \

            2      150

                    /     \

                  2        75

                           /    \

                         3       25

and 25 is 5^2

so 2^2 * 3* 5^2

So a is 2, since it's 2^2, b is 3, since it's 3^1, and c is 5, and d is 2.

If you don't understand anything feel free to ask.

Where's the table? 

Hi, what's your question?

Are you looking for the answer to 2007 AMC 10B Problem 8?

So 2/2000 = 1/1000.

so we have 1+1 + 3 + 4 + ... n /1000 < 1

So 2 + 3 + ... n < 1000

1 + 2 + 3... 50 = 51 * 25 = 1275, -1, 1274

1 + 2 + 3... 40 = 41 * 20 = 820, -1, 819

We have 1 + 2 + 3... 44 = 45 * 22 = 990, -1, 989

We can't go more. 

Thus n = 44

On the case that you messed up and it's 2/1000, it's still the same answer, but this time, added is 990.

If you don't understand anything feel free to ask.

Please arrange your latex properly.

There are no numbers at all.

Which implies you copied this from a site, presumbly AoPS.

I don't understand your question but just follow the order of operations to simplify.