hugomimihu

There are 2a students in the cooking club. b are in drama so 2a-b only in cooking

add a to drama so 3a-b students in at least one.

Thus we have 3a-b students in at least one of the clubs.

If you don't understand anything feel free to ask.

Here is a diagram that I hope will suit your needs.

I hope we have no more conflicts after this.

Also is EDT GMT-4, Eastern standard?

Thanks for clarifying, loki.

That is indeed what I meant.

(oops next time I'll do parentheses!)

Think of it this way. You pick any spot, and you have 2 points to either sides that are 1 unit away.

thus we have 7-2 /7 = 5/7 probability

if you don't understand anything feel free to ask!

i think Ziggy meant that you should go to Brainly or something for science and other things, this site revolves around math.

I got this for the gf(x)

3x^3+9x^2-12

Since I  multiplied the functions together

It doesn't make sense since if you have a x^2 already and multiply by x that's x^3

So I'm confused about the question.

f(f(x)) = 4 implies that f(x) must have been -1, or 4.5

This is since f(-1) = 4 and f(4.5) = 4

These are *probably* the only solutions

Onwards!

If the f(x) is -1, then it must mean that x = -4. -4 + 3 = -1. It cant be the solution from 2y-5 as it is negative.

for f(x) = 4.5, it is positive, so 2y-5 = 4.5

2y = 9.5

y = 4.75

Let's check our work.

f(f(-4)) = f(-4 +3) = f(-1) = -(-1) + 3 = 4!

f(f(4.75)) = f(9.5 -5) = f(4.5) = 9- 5 = 4

I am sure these are the only solutions

-4 + 4.75 = 0.75

If you don't understand anything feel free to ask!.

lol yeah

They do cars, all those.

Just in case you ever need to command a fleet.

You find the gcf of 120, 96, 168

Search up gcf of 120, 96 and 168

And it's not the best idea to split your fleet into small groups.

You should split them into groups with a few capital ships and a bunch of support/destroyers

it could also be (1,1,12)