IAmBadAtSolving

Do you mean 25% of the balls are red?

Probabilty oooo

First, the chance of getting 1 black ball.

$\frac{6}{9}$ aka $\frac{2}{3}$

Then, the chance of getting another one.

$\frac{5}{8}$because you already removed one, so total is 8, and 5 black balls left.

You times $\frac{2}{3}$by $\frac{5}{8}$ and you get $\frac{10}{24}$or $\frac{5}{12}$

Yeah, I wasn't sure if that was the question or not, and to not cause confusion I didn't post it.

I am so sure this has been posted, but the picture was gone, so I'm just gonna do it. 

First, we need to find the height and the bases.

How?. We can see that there is a 30-60-90 triangle!

Then, we can find the height. It is $\sqrt{3}$(You know this right?) Then the BIG base is 2+1+1 = 4.

Then using the formula, you get $\frac{2+4}{2}\sqrt{3}$ so the answer is $3\sqrt{3}$

Hope this helped!

Your welcome?!?!? Next time I'll try to credit the user- and put a picture if I'm not lazy-

Not trying to be rude or anything, but its decently easy, I copy and paste the whole thing, and look at results.

@below(Ahhhh the pictures to big)

(Should I post this? If not I will gladly delete this.)

This question has been asked here -------(address deleted)

Omi's answer from May 2018

A hint

You first can notice that the x number is 5/2 times bigger then the x+2 number(x is a number in the sequence).

Hoped my "hint" helped.

Or just do the math until you got the 10th number.

You don't have to use 6, 5 minutes, but still works

My answer to this is

You know there is 60 minutes in a hour, so for this question the answer will be 12:??

Then, after we find how much minutes left when it is 12:00, there is 25 more mintues. We add on 25, so 12:25

I am not the best at explaining, and I don't explain very much(new user and look at my username), so don't go attacking me. (I also skip like a lot of "simple" to me steps)

First, you can factor z^4 - 4z^2 + 4 = 0 into (z^2 -2)^2

I am assuming that you already know this, but i will still "explain"

You can turn z^4 - 4z^2 +4 = 0 into z^4 - 2z^2 - 2z^2 + 4

Then, you notice that you can factor that into z^2(z^2 - 2) -2(z^2 - 2)

Then, you can turn that into (z^2 -2)(z^2-2). Or, (z^2 - 2)^2.

You notice that $\sqrt{2}$, will work, and -$\sqrt{2}$. 

Because, $(\sqrt{2})^2$is equal to 0, (2-2)^2 = 0

And $(-\sqrt{2})^2$is also equal to 2.

I hope this helped?