In right triangle ABC, we have AB = 10, BC = 20, and angle ABC = 90 degrees. If M is on AC such that BM is a median of triangle ABC, then what is cos ABM?
This question has already been solved here!
That is great.
I like that you have used a link to Chris's answer.
Just one little suggestion.
Please put the address in the link so that people know where they are linking to.
I, for one, am wary about hyperlinking to unknown destinations.
