What is the area of the trapezoid shown? Express your answer in simplest exact form.![[asy] unitsize(1.5cm);pair a=(0,0); pair b=(1,sqrt(3)); pair c=(3,sqrt(3)); pair d=(4,0);draw(a--b--c--d--a);label(](/api/ssl-img-proxy?src=https%3A%2F%2Flatex.artofproblemsolving.com%2F3%2Fc%2F4%2F3c4675d5f3e80b23b27200e0b538b4fb8d19da26.png)
+33 I am so sure this has been posted, but the picture was gone, so I'm just gonna do it.
First, we need to find the height and the bases.
How?. We can see that there is a 30-60-90 triangle!
Then, we can find the height. It is \(\sqrt{3}\)(You know this right?) Then the BIG base is 2+1+1 = 4.
Then using the formula, you get \(\frac{2+4}{2}\sqrt{3}\) so the answer is \(3\sqrt{3}\)
Hope this helped!
+580 Yep, I was gonna say the same thing !!!!!
Also if you would like a different method of approaching the problem, Melody and CPhill have answered it in the link below:
https://web2.0calc.com/questions/what-is-the-area-of-the-trapezoid-shown-express-your-answer-in-simplest-exact-form
+33 Yeah, I wasn't sure if that was the question or not, and to not cause confusion I didn't post it.
