A drawer contains 3 white balls and 6 black balls. Two balls are drawn out of the box at random. What is the probability that they both are black?
+33 Probabilty oooo
First, the chance of getting 1 black ball.
\(\frac{6}{9}\) aka \(\frac{2}{3}\)
Then, the chance of getting another one.
\(\frac{5}{8}\)because you already removed one, so total is 8, and 5 black balls left.
You times \(\frac{2}{3}\)by \(\frac{5}{8}\) and you get \(\frac{10}{24}\)or \(\frac{5}{12}\)
+33 Probabilty oooo
First, the chance of getting 1 black ball.
\(\frac{6}{9}\) aka \(\frac{2}{3}\)
Then, the chance of getting another one.
\(\frac{5}{8}\)because you already removed one, so total is 8, and 5 black balls left.
You times \(\frac{2}{3}\)by \(\frac{5}{8}\) and you get \(\frac{10}{24}\)or \(\frac{5}{12}\)
