+1124 Hi friends,
what does it mean when they say to draw a parabola with the following properties:
Roots =0 differs by 4 - Does this mean the x-intercepts are 0 and 4?
and lastly, f ' (-2)=0..I know to get the turning point of a parabola, one needs to use the first derivative, so does this mean to give the turning point, indicating x=-2, y=0?
if I understand the above correctly, the graph cannot be drawn..please guide me with this..I do appreciate!
+118667 Have you abbreviated this Juriemagic?
It seems to have some words missing....
All I get from this is that it is a parabola with the axis of symmetry is x= -2
If the roots differ by 4... maybe it means that they are 4 units apart.
Maybe they are at (-4,0) and (0,0)
It could be concave up or concave down. The y value of the turning point cannot be determined.
So the most I can say is:
\(y=ax(x+4) \qquad \text{Where a is any real number.}\)
+1124 Hi melody,
oops, yes it is mentioned here that the range of f is \(y>=-2\)
sorry..
+118667 Well in that case it is concave up and the minimum is (-2,-2)
\(y=ax(x+4) \qquad \text{Where a is any real number.}\\ \text{passes though }(-2,-2)\\~\\ \text{Subthe point in}\\ -2=a*-2(-2+4)\\ -2=a*-4\\ a=\frac{1}{2}\\ \text{So the equation is}\\ y=0.5x(x+4)\\ y=\frac{x(x+4)}{2}\\ \)
LaTex
y=ax(x+4) \qquad \text{Where a is any real number.}\\
\text{passes though }(-2,-2)\\~\\
\text{Subthe point in}\\
-2=a*-2(-2+4)\\
-2=a*-4\\
a=\frac{1}{2}\\
\text{So the equation is}\\
y=0.5x(x+4)\\
y=\frac{x(x+4)}{2}\\
+1124 It's like a flower blooming...it really is not that difficult after all. In a certain sense I feel I have wasted your time on this...I should have been able to see this..anyways, as always, you are appreciated!!..Thank you..
