lokiisnotdead

Vertex: \([\dfrac{-b}{2a},f(\dfrac{-b}{2a})]\)

you already know that a = 4, b = -6, c = 15

all you have to do from here is plug in the values!

yea! it would be super cool to talk with animals! that one was a hard one to pick!

yes!!!

good job! you're on the right track! the numerator is correct, but the denominator isn't.

you got the 12 choose 3 part right, but not the rest.

think about it, if you've already chosen 3 cards, then there would be 12-3=9 cards left to choose from, not 8. 

you're really close! you got this!

:)))

hi guest!

so the first guy can draw 3 cards in \(\dbinom{12}{3}\) ways, and there are 4*4*4 possible draws that contain an ace, a 2, and a 3.

the second guy can draw 3 cards in \(\dbinom{9}{3}\) ways, and there are 3*3*3 possible draws that contain an ace, a 2, and a 3.

the third guy can draw 3 cards in \(\dbinom{6}{3}\) ways, and there are 2*2*2 possible draws that contain an ace, a 2, and a 3.

and, finally, the last guy just gets the remaining cards, which are an ace, a 2, and a 3.

so, the answer is \(\frac{4^3\cdot3^3\cdot2^3}{\binom{12}{3}\binom{9}{3}\binom{6}{3}}=\boxed{\frac{72}{1925}}\)

I hope this helped you!

:)

umm whymenotsmart, i think you're referring to a different problem?

hi guest!

So, if the Business class takes up 25%, that means it takes up \(\frac{1}{4}\) of all seats. Economy takes up \(\frac{2}{3}\). So, \(\frac{1}{4}\text{ Bsuiness seats}+\frac{2}{3} \text{ Economy seats}=\frac{11}{12}\)

That means, First class takes up \(\frac{1}{12}\) of the seats.

\(24=\frac{1}{12} \text{total seats}\)

\(\text{total seats}= \boxed{288}\)

I hope this helped you!

:)

yeah it's super confusing to me too :(((

ooh this looks fun!

1. meet my ancestors

2. depends on how much more money and how much more time...

3. hmm they're practically the same, but rewind i guess?

4. speak all foreign languages!

no problem! :)