lokiisnotdead

Hi Strawberrymilk.tae!

\(30 \text{ chocolates}-20 \text{ chocolates}=\boxed{10 \text { chocolates}.}\)

thank you so much for the clear and concise answer, I understand how to solve it now!!! I'm really thankful that there are people like you on the forum :)))

Hi Guest!
 

This is just \(9+18+27+36+45+54+63=\boxed{252}\).

Or \(9(1+2+3+4+5+6+7)=9(28)=\boxed{252}.\)

I hope this helped you, guest!

:)

Hi Guest!
 

This is a right triangle, so the hypotenuse would be \(6a+1\) since the hypotenuse is the longest side.

So, \((a+1)^2+(6a)^2=(6a+1)^2\).

\(a^2+2a+1+36a^2=36a^2+12a+1\)

\(a^2+2a=12a\)

\(a^2=10a\)

So, \(a=0, \text{ or } a=10\)

But, a length cannot be 0, so \(\boxed{a=10}!\)

I hope this helped you, guest!
:)

no its ok! i'm glad you learned something!!! :))))

hmmm I think CPhill is correct...

If you plug in 2 to the second equation, you get: \(2^2+3(2)-38=4+6-38=\boxed{-28}\)

And \(-28 \neq 2\)

umm I think you need to say how many girls and boys there are... :)

\(\frac{4}{5}=\frac{80}{100}=\boxed{80\%}\)

Hi Guest!