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Find all complex numbers \(z\) such that \(z^2=2i\).

 

 

thank you to anyone who helps! i really appreciate it! :)

 Jun 29, 2020
 #1
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The solutions are sqrt(2i) and -sqrt(2i).

 Jun 29, 2020
 #2
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yeah that's what i got too, but apparently, it's wrong...

lokiisnotdead  Jun 29, 2020

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