lokiisnotdead

Hi andrewstanells,

I'm not sure if my answer is right, but here's my solution anyways:

\(3^\frac{5}{4}=3^\frac{5}{4}\)

\(9^{\frac{3}{2}}=(3^2)^{\frac{3}{2}}=3^3\)

So, \(3^{\frac{5}{4}}\cdot3^3=3^{{\frac{5}{4}}+3}=\boxed{3^\frac{17}{4}}\)

So, \(\boxed{x=\frac{17}{4}}\)

I hope this helped you!

:)

yay that's right! thanks CPhill! :)

oh haha i didn't notice how easy the answer was 😅

thanks Melody!

Hi qwertyzz,

I'm really bad with these problems so this solution is probably wrong, but I'll give it a shot anyway!

If \(23=x^4+\frac{1}{x^4}\) then what is the value of \(x^2+\frac{1}{x^2}\)?

So how I did this is: 

First, I just set \(x^2+\frac{1}{x^2}=y\)

If you square both sides of \(x^2+\frac{1}{x^2}=y\), you get \((a^2)^2 + 2a^2\cdot\frac{1}{a^2} + \left(\frac{1}{a^2}\right)^{\!2} = y^2\). 

So, this means that \(a^4 + \frac{1}{a^4} = y^2-2\).

We know that \(a^4 + \frac{1}{a^4} =23\), so \(y^2-2=23\)

So, we know \(\boxed{y= \pm5}\)

I hope this was right?

Please tell me if this is right!

:)

Hi guest!

Since we know the 2 points, we can first use point-slope form and then convert it to slope-intercept form. 

Point slope form: \(y-y_1=m(x-x_1)\)

First let's find the slope. The slope is \(m=\frac{3-9}{6-9}=\frac{-6}{-3}=2\)

So, in point slope form we get \(y-9=2(x-9)\)

This is equal to \(y-9=2x-18\)

\(\boxed{y=2x-9}\)

I hope this helped you, guest!

:)

Hi guest!

So first of all, we know that the blank angle of the triangle is \(180-(w+47)^{\circ}\)since, it's a straight line.

We also know that 3 angles of a triangle sum to \(180^{\circ}\)(triangle theorem).

So, we know \(w+w+13+180-w-47=180\)

If we combine like terms and simplify, we get:

 \(w+146=180\)

\(\boxed{w=34^\circ}\)

We can check this too: 34+(34+13)+180-34-47=180

I hope this helped you, guest!

:)

Hi guest!

The answer is C. 

There are 3 black squares and 8 squares in total. So the ratio is 3/8. 

The only choice that doesn't work is C, because 3*7=21, but 8*7 does not = 21.

Hi guest!

The slope is 4/-2=-2 because it rises 4 up and goes 2 spaces to the left.

The y-intercept is 3 because it crosses the y axis at (0,3).

So, the equation of the line is \(\boxed{y=-2x+3}\).

I hope this helped you guest!

:)

Hi peepeepuupuu,

The formula for the midpoint is \((\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})\).

Because we know one of the endpoints is (1,6), that means we know that \((\frac{1+x_2}{2}, \frac{6+y_2}{2})=(3,-2)\).

So, we know

\(\frac{1+x}{2}=3\)

1+x=6

x=5

\(\frac{6+y}{2}=-2\) 

6+y=-4

y=-10

So, the other endpoint is \(\boxed{(5,-10)}\)!

I hope the helped you, peepeepuupuu!

PS your username made my immature self crack up :)

 \(\)