The midpoint of a line segment is located at (3,-2). If one of the endpoints is (1,6), what is the other endpoint? Express your answer as an ordered pair.

peepeepuupuu Apr 27, 2020

#1**+2 **

Hi peepeepuupuu,

The formula for the midpoint is \((\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})\).

Because we know one of the endpoints is (1,6), that means we know that \((\frac{1+x_2}{2}, \frac{6+y_2}{2})=(3,-2)\).

So, we know

\(\frac{1+x}{2}=3\)

1+x=6

x=5

\(\frac{6+y}{2}=-2\)

6+y=-4

y=-10

So, the other endpoint is \(\boxed{(5,-10)}\)!

I hope the helped you, peepeepuupuu!

PS your username made my immature self crack up :)

\(\)

.lokiisnotdead Apr 27, 2020

#2**+1 **

For** x ** from end point to midpoint is moving from 1 to 3 <---- a distance of 2 add 2 more to get to the other endpoint =** 5**

for **y ** from 6 to -2 a move of -8 add another -8 to get to ** -10**

ElectricPavlov Apr 27, 2020