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# help me ญ็็็็็

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The midpoint of a line segment is located at (3,-2). If one of the endpoints is (1,6), what is the other endpoint? Express your answer as an ordered pair.

Apr 27, 2020
edited by peepeepuupuu  Apr 27, 2020

#1
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Hi peepeepuupuu,

The formula for the midpoint is $$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$$.

Because we know one of the endpoints is (1,6), that means we know that $$(\frac{1+x_2}{2}, \frac{6+y_2}{2})=(3,-2)$$.

So, we know

$$\frac{1+x}{2}=3$$

1+x=6

x=5

$$\frac{6+y}{2}=-2$$

6+y=-4

y=-10

So, the other endpoint is $$\boxed{(5,-10)}$$!

I hope the helped you, peepeepuupuu!



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Apr 27, 2020
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For  from end point to midpoint is  moving from 1   to 3  <---- a distance of 2    add 2 more to get to the other endpoint = 5

for     from                                                             6 to -2    a move of -8  add another -8 to get to   -10

Apr 27, 2020