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The midpoint of a line segment is located at (3,-2). If one of the endpoints is (1,6), what is the other endpoint? Express your answer as an ordered pair.

 Apr 27, 2020
edited by peepeepuupuu  Apr 27, 2020
 #1
avatar+463 
+2

Hi peepeepuupuu,

 

The formula for the midpoint is \((\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})\).

Because we know one of the endpoints is (1,6), that means we know that \((\frac{1+x_2}{2}, \frac{6+y_2}{2})=(3,-2)\).

 

So, we know

\(\frac{1+x}{2}=3\)

1+x=6

x=5

 

 

\(\frac{6+y}{2}=-2\) 

6+y=-4

y=-10

 

So, the other endpoint is \(\boxed{(5,-10)}\)!

 

I hope the helped you, peepeepuupuu!

PS your username made my immature self crack up :)

 

 

 \(\)

.
 Apr 27, 2020
 #2
avatar+23701 
+1

For  from end point to midpoint is  moving from 1   to 3  <---- a distance of 2    add 2 more to get to the other endpoint = 5

for     from                                                             6 to -2    a move of -8  add another -8 to get to   -10

 Apr 27, 2020

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