The midpoint of a line segment is located at (3,-2). If one of the endpoints is (1,6), what is the other endpoint? Express your answer as an ordered pair.
Hi peepeepuupuu,
The formula for the midpoint is \((\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})\).
Because we know one of the endpoints is (1,6), that means we know that \((\frac{1+x_2}{2}, \frac{6+y_2}{2})=(3,-2)\).
So, we know
\(\frac{1+x}{2}=3\)
1+x=6
x=5
\(\frac{6+y}{2}=-2\)
6+y=-4
y=-10
So, the other endpoint is \(\boxed{(5,-10)}\)!
I hope the helped you, peepeepuupuu!
PS your username made my immature self crack up :)
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For x from end point to midpoint is moving from 1 to 3 <---- a distance of 2 add 2 more to get to the other endpoint = 5
for y from 6 to -2 a move of -8 add another -8 to get to -10