Melody

I think that you would look beautiful too Rosala :)

But the post was really funny - thanks Chris 

And Naus, your post is hilarious.

Maybe I should try pine tar and motor oil, but my hair is not black, it might look better on Rosala and Sasini.    

Thanks Alan  

Thanks anon,   

This is what Sydney's Life Savers look like.  

Thanks DavidQD,

I remember that snark question.

"How much tax would be on 113.98 at 9%"

I didn't mind the kids playing with it but I remember I became concerned because it was appearing with wrong date stamps and I though the web2 forum program had been hacked.  This is an interesting explanation of why that happened.    

Alan I had an answer similar to your first one but I got in a mess and scrubbed it.

If you are looking at this from a probabliliy perspective  I think that (or something very similar ) would be correct

but

from the choosers point of view without worrying about probabilities there are 19 possible outcomes.

So Ultmage  your answer is not correct.    

This is my 2 cent worth 

There are a number of was to look at this question.  If it was part of a probablitiy question you would assume every ball was numbered as well as coloured

BUT this is NOT a probablily question so I am going to interprete it differently

Added after:  The title is Permutation which means that Order Does Count

-----------------------------------

First interpretation:  order does not count.  Here are my choices.    

BBB, BBR, BBW, BRR, BWW, BRW         That makes 6 outcomes

--------------------------------

Now I am going to look at if order does count.

Here are the choices

BBB

BBR or BBW

BRB or BWB

RBB or WBB

Now if I  chose just 2 non-black ones then I can have  WW,WR,RW, or RR  now the black one can be 1st second or third      so that is   4*3=12

Total = 1+6+12=19 ways       [This is the only one with any validity out of my 3]

--------------------------------------------------------------

NOW LETS LOOK AT IT FROM AN ORDER DOES NOT COUNT PROBABILITY PERSPECIVE

Total number of ways that you can choose 3 b***s from 9 is 9C3=84

Total number of ways of not choosing any black ones is   6C3 = 20

There for total number of ways of haveing a black one in the mix must be 84-20=64

(This is the same answer as most the others got I think)

Lets do this the long way and see if there is any agreement

all black   3C3=1

2black and 1 other = 3C2*6C1=3*6=18

1black and 2 other = 3C1*6C2=3*15=45

1+18+45=64                                      GOOD IT IS THE SAME

P(choosing at least 1 black out of 3 where order doesnt count.) = 64/84

64 IS NOT THE CORRECT ANSWER BECAUSE THE TITLE OF THIS QUESTION IS PERMUTATION.

64 IS THE ANSWER TO A COMBINATION QUESTION SO IT IS NOT CORRECT  !!

---------------------------------------------------------------------

Now how about if order does count from a proabability perspective

It is all getting a bit much now.     

---------------------------------------------------------------------------

Yes :)

 log 3.000 = log3

 log 30.00 = log(10*3)=log10+log3=1+log3

 log 300.00= log(100*3)=log100+log3=2+log3

 log 3000= log(1000*3)=log1000+log3=3+log3

 log (3 x 10^12)= log(10^12*3)=log10^12+log3=1,000,000,000,000+log3

Sometimes it is tough being a kid.  

This type of thing happens to adults in their work places sometimes too.

It is never fun.  

BUT tomorrow will be better.    

$$\\\frac{5.12}{x} = \frac{.25}{.02}\\\\
$When I get entire fractions on both sides and x is on the bottom I just turn both sides upside down$\\\\
\\\frac{x}{5.12} = \frac{.02}{.25}\\\\
$now multiply both sides by 5.12$$$