Geno, I do not get your answer. 
do you mean that they both can't threaten each other at the same time? That is true. 
Assuming that there are no other peices in the way. And assuming that one is white and the other is black.
If a bishop is on any square it will be threatened if the castle is on the same row or the same column.
There are 7 squares left on the column and 7 on the same row and there are a total of 8*8-1=63 squares that the bishop could be on so
P(castle threatens bishop) = $${\frac{{\mathtt{14}}}{{\mathtt{63}}}} = {\frac{{\mathtt{2}}}{{\mathtt{9}}}} = {\mathtt{0.222\: \!222\: \!222\: \!222\: \!222\: \!2}}$$
NOW
The probability that the bishop threatens the castle is more complicated. 
I think I shall think about it later. LOL 