Melody

Yes whenever there is a complication in a question that gets in the way of grasping the technique needed, always get rid of it and look at an similar example with kinder numbers or letters.

I still do this quite regularly    

Ok you are getting there MG

Q2,3,4,8  all good

Q5 almost good

Rest need work.

Q6      You answer is good except that +- must be changed back to a - and there is not =0 in the question.

Q7     This is how it should be done

$$\\\frac{3x}{2}+\frac{4x}{5}\\\\
$You must get a common denominator that will be 10$\\\\
=\frac{3x*5}{2*5}+\frac{4x*2}{5*2}\\\\
=\frac{15x}{10}+\frac{8x}{10}\\\\
=\frac{15x}{10}+\frac{8x}{10}\\\\
=\frac{23x}{10}\qquad or\\\\
=2.3x\\\\$$

Q9)     0.06/0.3

you cannot divide by a decimal so you have to change at least the bottom (or both) into a whole number

$$\\\frac{0.06}{0.3}=\frac{0.06*10}{0.3*10}=\frac{0.6}{3}=0.2\qquad \\\\
or\\\\
\frac{0.06}{0.3}=\frac{0.06*100}{0.3*100}=\frac{6}{30}=\frac{1}{5}\quad or\;=0.2$$

Q11)

This was my question

$$\frac{5x+2}{6y}\times9xy^2$$

but when you rewrote it you wrote                  

5x+2/6y*9xy^2         this is entirely different expression!  I will show you the expression you have written.

$$5x+\frac{2}{6}*y*9xy^2=5x+\frac{2y}{6}*9xy^2\\\\$$        

So before you try to simplify my Q11  I would like you to write it properly without the aid of LaTex.

 In other words, where do you need to put brackets!       [ always remember PEDMAS ]

Just think about it logically Zac,  I'll use a simpler example

$$k^2>25$$

 If k=6 then k^2=36 so this makes the statement true

If k=-6 then x^2=36 so this makes the statement true too.

For any value of k between -5 and +5 the statement will be false.

So it will be true when

k>5   and when  k<-5

It may help you understand if you draw a number line.  I often think of number lines when I answer inequalities.

Have I answered your question or were you hoping for something different ?

You're tough.  You can take it.    Hahaha 

Yes Chris made a boo boo.  He's all tuckered out.  He has been out mowing his lawn.  That's the problem :)

It was really slow going too because the grass was really long and he was frightened he'd go over the top of the Roman Zero and chop it into little pieces and then he would never be able to get his problems correct.  

He'd be in big trouble with the Gods too....

I can try :)

Our numbers are in base 10.  That means we use 10 digits 0,1,2,3,4,5,6,7,8 and 9

If I write this number 

3658 it is the number $$3*10^3+6*10^2+5*10+8*1=3000+600+50+8$$

I can also write it like this  $$3658_{10}$$     The little 10 means that it is base 10.

NOW

Mellie's numbers are not base 10

she has  332 base 4 and 212 base 3

$$\\332_4\\
$if I convert this to base 10 I get$\\
=3*4^2+3*4+2\\
=3*16+12+2\\
=48+12+2\\
=62\\\\\\
212_3\\
$if I convert this to base 10 I get$\\
=2*3^2+1*3+2*1\\
=2*9+3+2\\
=18+3+2\\
=23$$

The i just had to do the subtraction :)

Do you get it ?

Hi Mellie,

1)

   $$\\332_4-212_3\\
=(3*4^2+3*4+2)-(2*3^2+1*3+2)\\
=(3*16+12+2)-(2*9+3+2)\\
=62-23\\
=39$$

 2)

 $$\\\frac{a}{a+27}=\frac{865}{1000}\\\\
\frac{a+27}{a}=\frac{1000}{865}\\\\
1+\frac{27}{a}=\frac{1000}{865}\\\\
\frac{27}{a}=\frac{1000-865}{865}\\\\
\frac{27}{a}=\frac{27}{173}\\\\
a=173$$

3)

$${\frac{{\mathtt{5}}}{{\mathtt{33}}}} = {\mathtt{0.151\: \!515\: \!151\: \!515\: \!151\: \!5}}$$ 

2nd place is 5, 4th place is 5 all the even places are 5 SO the 92nd place is 5

Thanks Rosala :)

Mmm , we will see how it goes.  :))

You seem to have generated a lot of interest already :)