Simplify x(40-2x)(40-2x) over -4xsquared + 1600
If what I have done is what you meant then this would have been the best way to present it.
Simplify [ x(40-2x)(40-2x) ] / [ -4x^2 + 1600 ] 
I have used difference of 2 squares to factoise the bottom, that is \(a^2-b^2=(a-b)(a+b)\)
\(\frac{x(40-2x)(40-2x)}{-4x^2+1600}\\ =\frac{x(40-2x)(40-2x)}{1600-4x^2}\\ =\frac{x(40-2x)(40-2x)}{(40)^2-(2x)^2}\\ =\frac{x(40-2x)(40-2x)}{(40-2x)(40+2x)}\\ =\frac{x(40-2x)}{(40+2x)}\\ =\frac{x\times 2(20-x)}{2(20+x)}\\ =\frac{x(20-x)}{20+x}\\ or\\ =\frac{20x-x^2}{20+x}\\\)
Thanks guest, I have only just seen you answer, it was not there when I started :))
NOTE: The 2 answers are the same.