Draw it!
The centre is obviously (-3,1) so this gives h and k
and it is going to have a vertical axis.
\(\frac{(y - k)^2}{a^2} - \frac{(x - h)^2}{b^2} = 1\)
c is the distance from the centre to a focus so \(c=\frac{\sqrt5}{4}\)
\(|PF_1-PF_2|=1=2a\\ so\;\;\;a=0.5\)
Then you have \(c^2=a^2+b^2\)
so you can find b
Not so difficult after all.