Melody

Is this meant to be a computing question or a maths question?

Thanks Alan,

For ignorant people like myself, this might be of interest.

Tidy up both equations independently.   

Then solve them simultaneously,

I used the elimination method and the answer got was very tidy. (no horrible decimals)

note that I have not checked my answer though.

Can you have a go at it now?

I got a different answer.

\(let\;\;r=x+\delta\qquad \)   Where x is an integer and     \(0\le\delta<1\)

then the problems becomes 

\(\lfloor r \rfloor + r = 15.5\\ x+x+\delta=15.5\\ \)

I will leave you to think about this and to determine for yourself how many solutions that there are.

Just calculate f(3) and g(3) and add them together.

Well we cannot divide by 0 so

\(x\ne0\)

\(1+\frac{1}{x}\ne0\\ \frac{1}{x}\ne-1\\ x\ne-1 \)

\(1+\frac{1}{1+\frac{1}{x}}\ne0\\ \frac{1}{1+\frac{1}{x}}\ne-1\\ \frac{x}{x+1}\ne-1\\ x\ne -x-1\\ 2x\ne-1\\ x\ne -\frac{1}{2}\)

Can you do any of it?

Can you work our the equation of either of those two lines?

Is it just Web 2.0 or other things as well,  perhaps it is everything?

They all look good to me.

It does not say that the hand should be at 10 to 2.

It says the hands should be on 10 and 2.

This is not a time question.