\(\displaystyle \lim_{x\rightarrow 0} \;\frac{x}{tanx} =1\)
I think this is one of those things that you are meant to memorize.
\(\frac{2x^2 - 3x}{(x^2 - x) }+ 5x - 11 =\frac{ (3x^2 + 4)}{(x^2 - 1)}\)
Start by factorizing the numerators and the denominators of the fractions.
Cancel out common factors
Then get back to us with what you have.
What is the sine rato?
(Your turn to ansswer)
That is not the right answer.
I used the euclidean algorithm to solve this :
https://www.youtube.com/watch?v=fz1vxq5ts5I
But the answer is only a little so you could start at 1 then work up until you find the answer.
How about proofreading your question. It is nonsense.
The first ball can go in any of the 3 boxes, that is 3 ways
the second ball can go int any of the 3 boxes that together with the first ball is 3*3=3^2=9 way
so for 6 balls it would be 3^6 ways.
Why don't you tell us your thoughts first?
Thanks for providing us with the solution abc ...
I am sure a number of us will examine it
Here is Alan's answer graphed, from Desmos.
I wouldn't guess that this was a degree 5 polynomial. (without doing lots of work)
Although it would have to be an odd degree. That makes 5 reasonable I guess.