Thank you Kitty, that is a good answer.
However, I would also like to see this done using combination notation.
Yes, that is correct
I'll take your word for it Foxtears but you should point out that it is an approximation.
If you use the Math(Input=Result) button above to access the site calc it would be much easier for people to check your anwer.
Like this.
$${\sqrt{{\mathtt{128\,745}}}} = {\mathtt{358.810\: \!534\: \!962\: \!394\: \!882}}$$
$$5\times 8\sqrt2=40\sqrt2$$
$$C=2\pi r = \pi r+ \pi r\\ A=\pi r^2 = \pi\times r\times r$$
$$\pi\times C=\pi \times 2\pi r = 2\pi^2r\ne A$$
Does that help?
Thanks reinout-g
The solution give is
$$e^{2ln3}=e^{ln9}=9$$ This is correct for this question, however,
The question as written is
$$e^2ln3$$ and I do not believe this question can be simplified - although you could use a calc to estimate the answer.
Look here
http://web2.0calc.com/questions/how-do-i-type-in-fractions
If this is not what you meant then you need to learn to use brackets properly.
Only 2 factors - 1 and itself - hence 31 is a PRIME NUMBER
+118725 
