Melody

43*4.2 metres

That is assuming that the 43m/s is a horizontal speed and that the ball stays in the air for the whole 4.2 seconds.

It also ignores air resistance, wind etc   

sin-1 is the same as arcsine

so you use 

asin

$$\sqrt3(-16xy^6)\\\\
=-16\sqrt3xy^6\\\\\\
$or do you mean$\\\\
\sqrt{3(-16xy^6)}\\\\
=\sqrt{-3*16xy^6}\\\\
=4y^3\sqrt{-3x}\\\\
=4y^3\sqrt{3x}\;i\\\\
\;$i is the imaginary number $\sqrt{-1}$$

$$log_3\left(\dfrac{1}{3^1\;3^{0.5}}\right)+2\\\\
=log_3\left(\dfrac{1}{3^{1.5}}\right)+2\\\\
=log_3\left(3^{-1.5}\right)+2\\\\
=-1.5log_3\left(3\right)+2\\\\
=-1.5*1+2\\\\
=-1.5+2\\\\
=0.5$$

You use inverse sine 0.45

$$sin^{-1}0.45$$

On the web2.0 calc this is  arc sin

arc sin is the same as invers sine

[2nd] [asin] 0.45

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}^{\!\!\mathtt{-1}}{\left({\mathtt{0.45}}\right)} = {\mathtt{26.743\: \!683\: \!950\: \!403^{\circ}}}$$

This graph has a horizontal asymtote at y=-1

$$109^7=429^a\\\\
log109^7=log429^a\\\\
7log109=a*log429\\\\
a=\frac{7log109}{log429}$$

$${\frac{{\mathtt{7}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{109}}\right)}{{log}_{10}\left({\mathtt{429}}\right)}} = {\mathtt{5.417\: \!746\: \!197\: \!792\: \!286}}$$

Well

5%=5/100

50%=50/100=1/2

100%=100/100=1

600%=600/100=6

5000%=5000/100=50

0%=0

so

5000%+0%=50+0=50

Thanks Chris, I keep forgetting about L'Hopital's Rule !!

Thanks anon

There is 2nd  meaning

In a degree of a polynomial is the highest power of x

eg

$$y=5x^7-3x^2+x-2$$

Has a degree of 7