mworkhard222

He/she probably copied it from somewhere else and the $\LaTeX$ didn't show up

best answer yayyyy

yes, tysm

$\frac{\sqrt{160}}{\sqrt{252}}\cdot \frac{\sqrt{245}}{\sqrt{128}}$

$=\frac{7\sqrt{5}}{8\sqrt{2}}\cdot \frac{2\sqrt{10}}{3\sqrt{7}}$

$=\frac{2\sqrt{10}\cdot 7\sqrt{5}}{3\sqrt{7}\cdot 8\sqrt{2}}$

$=\frac{14\sqrt{10}\sqrt{5}}{24\sqrt{7}\sqrt{2}}$

$=\frac{\sqrt{7}\sqrt{10}\sqrt{5}}{12\sqrt{2}}$

$=\frac{\sqrt{7}\sqrt{2}\sqrt{5}\sqrt{5}}{2^2\cdot \:3\sqrt{2}}$

$=\frac{5\sqrt{7}}{3\cdot \:2\sqrt{2}\sqrt{2}}$

$=\frac{5\sqrt{7}}{12}$

pray that i didn't mess up

thanks! but it's 60

no prob!

$\frac{2}{25}-\frac{14}{25}i$ i think

ok thanks

wait u put 8 as the height but the problem says 6