For how many integers nn where 2≤n≤1002≤n≤100 is (n2)(n2) odd?
n has to be odd because \(odd^2=odd\)
It cannot be even because \(even^2=even\)
So how many integers from 2 to 100 are odd?
The answer would be 49 integers
All odd numbers between 3 and 99 will be odd when squared. So, you have:
[99 - 3] / 2 + 1 =
96 / 2 + 1 =
48 + 1 = 49 numbers whose squares will be odd. Eamples: 3^2=9, 5^2=25, 7^2=49 and so on.