Nice work guys. :)
I like the display Aziz. Do you just use a paint program to make these?
Yup, the product of x and 7 is x times 7, or you could also write this as 7x.
First do the operation in the furthest parentheses.
$$\begin{array}{l} \frac{20}{(4-\bf{(10-8)})}\\\\ \frac{20}{(4-(2))}\\\\ \frac{20}{(4-2)}\\\\ \frac{20}{2}\\\\ \frac{10}{1}\\\\ 10\\\\ \end{array}$$
Either there's missing information...or this a trick question.
"calculate the capacity of a pool that is circular, has 300mm depth aand has the capacity of 1kl"
The capacity is just 1kl.
An interger is basically any positive or negative whole number.
An integer is not a positive or negitive decimal/fraction though.
This explained it really well: http://www.mathsisfun.com/whole-numbers.html
Just write this algebraicly and solve. This will give you the closest value of x.
$$\begin{array}{l} 4 \times x = 560\\\\ 4x=560\\\\ \frac{4}{4}x=\frac{560}{4}\\\\ x = \frac{560}{4}\\\\ x = 140 \end{array}$$
$$Notice that 40 is really the same thing as $\frac{40}{1}$\\ So now we have:\\ $\frac{3}{5} \times \frac{40}{1} = \frac{3\times40}{5\times1} = \frac{120}{5}\\$ We can reduce this fraction by dividing the top and bottom by 5\\ $\frac{120 \div5}{5\div5} = \frac{24}{1} = \mathbf{24}$$$
That kind-of makes sense. I get why you can do
(7/5x - 12) = 3
but why can you do
(7/5x - 12) = -3 ?
You lost me there...
No problem. Glad to help. :)
Thanks guys. I tried to explain it pretty well so our questioner could solve his other problems aswell.
There may be a little bit of unnecessary information. :)