20/(4-(10-8))

Question

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20/(4-(10-8))

Guest Aug 17, 2014

+3454

+8

Best Answer

First do the operation in the furthest parentheses.

$$\begin{array}{l}
\frac{20}{(4-\bf{(10-8)})}\\\\
\frac{20}{(4-(2))}\\\\
\frac{20}{(4-2)}\\\\
\frac{20}{2}\\\\
\frac{10}{1}\\\\
10\\\\
\end{array}$$

NinjaDevo Aug 17, 2014

NinjaDevo · Answer 1 · 2014-08-17T02:31:22

First do the operation in the furthest parentheses.

$$\begin{array}{l}
\frac{20}{(4-\bf{(10-8)})}\\\\
\frac{20}{(4-(2))}\\\\
\frac{20}{(4-2)}\\\\
\frac{20}{2}\\\\
\frac{10}{1}\\\\
10\\\\
\end{array}$$