NinjaDevo

I'm thinking you mean:

√(-1 - -3)+(4- -4)^2

We have to start by doing the things in the parentheses, because this comes first in the order of operations.

√(-1 - -3)+(4- -4)^2                ---Remember, subtracting a negative is the same as adding a positive

√(-1 + +3)+(4+ +4)^2

√(-1+3)+(4+4)^2

√(2)+(8)^2                           ---Now we do 8^2, because exponets come next in the order of operations.

√2+64

√66, or about 8.124

Here we need to get x alone on one side. This will tell us what x equals.

1/3(2x-3)=5

Now we need to use the distributive property. We can't do the operation in the parentheses, (2x-3) so we have to distribute 1/3 into both 2x and -3. To do this we multiply 1/3 times 2x, and add that to 1/3 times -3.

1/3(2x-3)=5

(1/3*2x)+(1/3*-3)=5

(2/3x)+(-3/3)=5

2/3x + (-1) = 5

2/3x - 1 = 5             ---Add 1 to both sides to "clear" -1 from the left side

       + 1   +1

----------------

2/3x = 6                 ---Multiply both sides by 3 to "clear" /3 from the left side

2x = 18                 ---Divide both sides by 2 to "clear" the 2 in 2x from the left side

x = 9

This probably looks something like this:

To figure out the area, you multiply all three lengths, so

7 x 4 x 3

28 x 3

84

There would be 84 cubic feet in this shape.

The turkey needs to cook 3 minutes per pound, and it weighs 12 pounds.

This means 3 x 12 will tell us the total minutes it will take to cook all the pounds.

3 x 12 = 36

The turkey will need to cook for 36 minutes, and he needs it ready at 5:00 pm

1 hour is 60 minutes, so 5:00 pm could really be:

4:60 pm

Let's subtract 36 minutes from this 

4:60

-  36

4:24

So the latest he can start cooking is 4:24 PM.

Here we have to set up two equations (or a system of equations), and then solve them for the two different teams (home team, and away team).

First, we know that there is 80 people, and this is made up of home team members (h) and away team members. (a) This means:

80 = a + h

Now we need to make a sencond equation, because we cacn't solve for a and h with just this information. a and h could be pretty much anything!

We are given that the number of home team fans (h) was 68 less than 3 times the number of away team fans (a)

This means:

h = (3 times a) - 68              ---Simplifies to:

h = 3a -68

Alright, now we have our two equations.

Let's subtract h from both sides on the first equation, and then we can "add" this equation to the second one, and we can find a.

80 = a + h              ---This was our first equation, subtract h from btoh sides to "clear" h from the right side

-h + 80 = a             ---Now "add" this to the second equation. This is called solving by elimination.

h = 3a -68             ---Second equation

---------------

80 = 4a - 68              ---Add 68 to both sides to "clear" -68 from the right side

80 + 68 = 4a

148 = 4a                   ---Now divide 4 from both sides to "clear" the 4 from 4a on the right side

37 = a

This means there was 37 fans from the away team.

To find how many people from the home team were there, we put 37 in for a (because a = 37) and solve for h. Let's take the first equation and do this.

80 = a + h               ---First equation

80 = (37) + h          ---Put 37 in for a, subtracrt 37 from both sides to "clear" 37 from the right side

43 = h    

So there was 43 home team fans there.

Whew, that was a long one! My fingers need a break now. :)

We have to turn the first set of numbers (7 2/5) into an inproper fraction first.

To do this, we multiply 7 (first number) times the bottom number, add the top number to that, and put the answer over 5 (bottom number).

$$7\frac{2}{5} = \frac{7\times5+2}{5} = \frac{35+2}{5} = \frac{37}{5}$$

Now we have:

$$\frac{37}{5} \div \frac{1}{5}$$

Remember SKIP, CHANGE, FLIP. When we divide two fractions, we SKIP the first fraction, CHANGE the division to a multiplication sign, and FLIP the second fraction. Now we get:

$$\frac{37}{5}\times\frac{5}{1}$$

And now we multiply the top numbers together, then multiply the bottom numbers together.

$$\frac{37\times5}{5}$$

$$\frac{185}{5}$$

And now simplify the fraction by dividing teh top and bottom by 5.

$$\frac{185\div5}{5\div5}$$

$$\frac{37}{1}$$

which is really....

$$37$$

This is simple interest, which means every year you gain 3% of $1200. You gain this for two years, so we have:

1200 + (3% of 1200) + (3% of 1200)

1200 + (0.03 x 1200) + (0.03 x 1200)

1200 + (36) + (36)

1272

There will be $1,272 in the account after 2 years.

Here we need to find c. To do this we need c alone on one side. Here's how we'd solve this:

Simply divide the top number by the bottom number. So, it would look like this:

$$\frac{1}{8}=1\div8 = 0.125$$

$$\begin{array}{l}
\frac{-1}{-2}\times4\\\\
\frac{-1}{-2}\times\frac{4}{1}\\\\
\frac{-1\times4}{-2\times1}\\\\
\frac{-4}{-2}\\\\
\frac{+4}{+2}\\\\
\frac{4}{2}\\\\
\frac{2}{1}\\\\
2
\end{array}$$