we know that one angle is \(30^\circ\) and another is \(90^\circ\) and the sum of all the angles in a triangle is \(180^\circ\) so we know that the third angle = 180 - 30 - 90 = \(60^\circ\) and so the triangle is a 30-60-90 degree triangle and since \(\overline{CA}\)= 6 then \(\overline{CB} = \overline{CA} \cdot 2=12 ~ and~ \overline{AB} = \overline{CA}\sqrt{3} = 6\sqrt3\) and the area is \(\frac{6\cdot6\sqrt{3}}{2}=\frac{6\cdot6\cdot\sqrt{3}}{2}=\frac{36\sqrt3}{2}=\boxed{18\sqrt3}\)
Maybe the moderator thinks you are not really answering the question?
well the question asks what the solid is
it is not very easy to see me on the leaderboard
and answers
get lots of hearts
Am I right?
I'm really sure this is right
