what is \(\frac{2^2 \cdot 2^{-3}}{2^3 \cdot 2^{-2}}?\)
22-3 / 23-2 = 2-1 / 2 = 1/(2*2) = 1/4
thanks
You're welcome !
well the negtive and positive cancel out to become (2^-1)/(2^1)= (1/2)/2=4 so our final answer is 4
