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We have a triangle \(\triangle{ABC}\) such that \(AB = 6, BC = 8,\)  and \(CA = 10.\) If \(AD\) is an angle bisector such that \(D\) is on \(BC\) then find the value of \(AD^2\)

 Aug 4, 2020
 #1
avatar+1154 
+1

We know that this is a right triangle since it has pythagorean triples 

 

see here:

 

https://www.geogebra.org/calculator/hty44jpe

 

I plotted here

 Aug 4, 2020
 #2
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AD^2 = 45.

 Aug 14, 2020

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