We have a triangle \(\triangle{ABC}\) such that \(AB = 6, BC = 8,\) and \(CA = 10.\) If \(AD\) is an angle bisector such that \(D\) is on \(BC\) then find the value of \(AD^2\)
We know that this is a right triangle since it has pythagorean triples
see here:
https://www.geogebra.org/calculator/hty44jpe
I plotted here
AD^2 = 45.
+315 
