+0

+1
126
6
+254

Find the area of triangle ABC  below.

Jul 30, 2020

#4
+347
+3

we know that one angle is $$30^\circ$$ and another is $$90^\circ$$ and the sum of all the angles in a triangle is $$180^\circ$$ so we know that the third angle = 180 - 30 - 90 = $$60^\circ$$ and so the triangle is a 30-60-90 degree triangle and since $$\overline{CA}$$= 6 then $$\overline{CB} = \overline{CA} \cdot 2=12 ~ and~ \overline{AB} = \overline{CA}\sqrt{3} = 6\sqrt3$$ and the area is $$\frac{6\cdot6\sqrt{3}}{2}=\frac{6\cdot6\cdot\sqrt{3}}{2}=\frac{36\sqrt3}{2}=\boxed{18\sqrt3}$$

Jul 30, 2020
#5
+1169
+1

so since we know that this is a 30-60-90 triangle the base is 6sqrt3 and we can find that the area is 6*6sqrt3=36sqrt3 we then fivide by 2 to get 18sqrt3

The area of the triangle is $$\Huge{18\sqrt3}$$

Jul 30, 2020