How many values of x with \(0^\circ \le x < 360^\circ\) satisfy \(\sin x = -0.73\)?

polyyou Aug 3, 2020

#2**+2 **

it is correct!

my explaintion is:

For each point on the unit circle with y-coordinate equal to -0.73, there is a corresponding angle whose sine is -0.73. There are two such points; these are the intersections of the unit circle and the line y=-0.73, shown in red above. Therefore, there are 2 values of x with \(0^\circ \le x < 360^\circ\) such that \(\sin x = -0.73\).

polyyou Aug 3, 2020