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# help me please on precalculus

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+344

How many values of x with $$0^\circ \le x < 360^\circ$$ satisfy $$\sin x = -0.73$$?

Aug 3, 2020

#1
+1154
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There are 2 values,  x=226.88639405,313.11360594.

Aug 3, 2020
#2
+344
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it is correct!

my explaintion is:

For each point on the unit circle with y-coordinate equal to -0.73, there is a corresponding angle whose sine is -0.73. There are two such points; these are the intersections of the unit circle and the line y=-0.73, shown in red above. Therefore, there are 2 values of x with $$0^\circ \le x < 360^\circ$$ such that $$\sin x = -0.73$$.

Aug 3, 2020
#3
+1

well good explaintion

Guest Aug 4, 2020