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How many values of x with \(0^\circ \le x < 360^\circ\) satisfy \(\sin x = -0.73\)?

 Aug 3, 2020
 #1
avatar+1128 
-1

There are 2 values,  x=226.88639405,313.11360594.

 Aug 3, 2020
 #2
avatar+338 
+2

it is correct!smiley

my explaintion is:



For each point on the unit circle with y-coordinate equal to -0.73, there is a corresponding angle whose sine is -0.73. There are two such points; these are the intersections of the unit circle and the line y=-0.73, shown in red above. Therefore, there are 2 values of x with \(0^\circ \le x < 360^\circ\) such that \(\sin x = -0.73\).

 Aug 3, 2020
 #3
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+1

well good explaintion

Guest Aug 4, 2020

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