+14538 +14538 +14538 +14538 +14538 +14538 +14538 +14538 +14538 +14538 +14538 +14538 +14538 +14538 #3
+14538 Hallo Anonymous,
$${{\mathtt{e}}}^{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)} = {{\mathtt{e}}}^{\left(-{\mathtt{5}}\right)}$$ => $${{\mathtt{e}}}^{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{5}}\right)} = {\mathtt{1}}$$ => $${\mathtt{x}} = {\mathtt{\,-\,}}{\frac{{\mathtt{5}}}{{\mathtt{2}}}}$$
2x*log(e) = -5*log(e) => 2x = -5 => x = -2,5 = - 5/2
Die Aufgabe $${{\mathtt{e}}}^{\left({\mathtt{0.5}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)} = {{\mathtt{e}}}^{\left({\mathtt{0.5}}{\mathtt{\,\times\,}}{\mathtt{x}}\right)}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}$$ hat keine Lösung !
0,5x = 1,5x !!! => 0,5 = 1,5 !!!
Gruß radix 
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